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21. * MULTIPLe CHOICE A car used 15 gallons of ga

21. * MULTIPLe CHOICE A car used 15 gallons of ga

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Question

    • MULTIPLe CHOICE A car used 15 gallons of gasoline and traveled a total distance of 350 miles. The car’s fuel efficiency is 25 miles per gallon on the highway and 20 miles per gallon in the used on the find hh, the number of gallons that were
      (A) 350=25(15h)+20h350=25(15-h)+20 h
      (D) 15=35025h+35020h15=(350)/(25 h)+(350)/(20 h)
      (C) 350=(25+202)h350=((25+20)/(2))h

Best Answer

To solve the problem, we can use the formula for distance traveled given the fuel efficiency and the number of gallons used:
distance=fuelefficiency×gallonsdistance=fuelefficiency xx gallons
Plugging in the given values, we have:
350=25h+20(15h)350=25 h+20(15-h)
Simplifying the equation, we get:
350=25h+30020h350=25 h+300-20 h
Subtracting 300 from both sides, we get:
50=5h50=5h
Dividing both sides by 5, we get:
h=10h=10
So, the number of gallons used on the highway was h=10h=10 gallons.
Therefore, the answer is option (B)350=25(15h)+20h(B)350=25(15-h)+20 h.